43z^2+36z=0

Solution for 43z^2+36z=0 equation:

43z^2+36z=0

a = 43; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·43·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*43}=\frac{-72}{86}
=-36/43
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*43}=\frac{0}{86}
=0
$